The number 80993
80993 is a composite number with 8 divisors. Its prime factorisation is 11 × 37 × 199. Divisors (8): 1, 11, 37, 199, 407, 2189, 7363, 80993.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
80993 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
80993 is composite. Its prime factorisation is
- 3
The divisors add up to 91200; without 80993 itself that is 10207, so 80993 is deficient (10207 is less than 80993). Euler's totient φ(80993) = 71280 numbers up to 80993 share no factor with it.
- 4
The digits of 80993 add up to 29, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 244 steps to reach 1.
LaTeX source of the formulas on this page
\[ 80993 = 11 \times 37 \times 199 \]
80993 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 91200 |
| Euler totient φ(n) | 71280 |
| Square | 6559866049 |
| Cube | 531303230906657 |
| Square root | 284.592691 |
| Digit sum / digital root | 29 / 2 |
| Collatz steps to 1 | 244 |
| Scientific notation | 8.0993 × |
80993 in other forms
| Form | Value |
|---|---|
| In words | eighty thousand nine hundred and ninety-three |
| Binary (base 2) | 10011110001100001 |
| Octal (base 8) | 236141 |
| Hexadecimal (base 16) | 13C61 |
| Base 3 | 11010002202 |
| As time | 80993 seconds = 22 h 29 min 53 s |
Is 80993 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | Yes (80993 ÷ 11 = 7363) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 80993 a prime number?
No. 80993 = 11 × 37 × 199, so it is divisible by 11.
What are the factors of 80993?
1, 11, 37, 199, 407, 2189, 7363, 80993.
What is 80993 in binary?
10011110001100001 (hexadecimal 13C61, octal 236141).
What is the square root of 80993?
About 284.5927.
Is 80993 divisible by 3?
No. Its digits add up to 29, which is not a multiple of 3.
What is special about the number 80993?
It is a composite number with 8 divisors.