The number 80983
80983 is a composite number with 8 divisors. Its prime factorisation is 7 × 23 × 503. Divisors (8): 1, 7, 23, 161, 503, 3521, 11569, 80983.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
80983 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
80983 is composite. Its prime factorisation is
- 3
The divisors add up to 96768; without 80983 itself that is 15785, so 80983 is deficient (15785 is less than 80983). Euler's totient φ(80983) = 66264 numbers up to 80983 share no factor with it.
- 4
The digits of 80983 add up to 28, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 76 steps to reach 1.
LaTeX source of the formulas on this page
\[ 80983 = 7 \times 23 \times 503 \]
80983 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 96768 |
| Euler totient φ(n) | 66264 |
| Square | 6558246289 |
| Cube | 531106459222087 |
| Square root | 284.575122 |
| Digit sum / digital root | 28 / 1 |
| Collatz steps to 1 | 76 |
| Scientific notation | 8.0983 × |
80983 in other forms
| Form | Value |
|---|---|
| In words | eighty thousand nine hundred and eighty-three |
| Binary (base 2) | 10011110001010111 |
| Octal (base 8) | 236127 |
| Hexadecimal (base 16) | 13C57 |
| Base 3 | 11010002101 |
| As time | 80983 seconds = 22 h 29 min 43 s |
Is 80983 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (80983 ÷ 7 = 11569) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 1) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 80983 a prime number?
No. 80983 = 7 × 23 × 503, so it is divisible by 7.
What are the factors of 80983?
1, 7, 23, 161, 503, 3521, 11569, 80983.
What is 80983 in binary?
10011110001010111 (hexadecimal 13C57, octal 236127).
What is the square root of 80983?
About 284.5751.
Is 80983 divisible by 3?
No. Its digits add up to 28, which is not a multiple of 3.
What is special about the number 80983?
It is a composite number with 8 divisors.