The number 80743
80743 is a composite number with 4 divisors. Its prime factorisation is 13 × 6211. Divisors (4): 1, 13, 6211, 80743.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 80743: a semiprime: 13 × 6211, the product of two primes.
- 2
80743 is composite. Its prime factorisation is
- 3
The divisors add up to 86968; without 80743 itself that is 6225, so 80743 is deficient (6225 is less than 80743). Euler's totient φ(80743) = 74520 numbers up to 80743 share no factor with it.
- 4
The digits of 80743 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 169 steps to reach 1.
LaTeX source of the formulas on this page
\[ 80743 = 13 \times 6211 \]
80743 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 86968 |
| Euler totient φ(n) | 74520 |
| Square | 6519432049 |
| Cube | 526398501932407 |
| Square root | 284.153128 |
| Digit sum / digital root | 22 / 4 |
| Collatz steps to 1 | 169 |
| Scientific notation | 8.0743 × |
80743 in other forms
| Form | Value |
|---|---|
| In words | eighty thousand seven hundred and forty-three |
| Binary (base 2) | 10011101101100111 |
| Octal (base 8) | 235547 |
| Hexadecimal (base 16) | 13B67 |
| Base 3 | 11002202111 |
| As time | 80743 seconds = 22 h 25 min 43 s |
Is 80743 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 80743 a prime number?
No. 80743 = 13 × 6211, so it is divisible by 13.
What are the factors of 80743?
1, 13, 6211, 80743.
What is 80743 in binary?
10011101101100111 (hexadecimal 13B67, octal 235547).
What is the square root of 80743?
About 284.1531.
Is 80743 divisible by 3?
No. Its digits add up to 22, which is not a multiple of 3.
What is special about the number 80743?
80743 is a semiprime: 13 × 6211, the product of two primes.