The number 80733
80733 is a composite number with 8 divisors. Its prime factorisation is 3 × 17 × 1583. Divisors (8): 1, 3, 17, 51, 1583, 4749, 26911, 80733.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
80733 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
80733 is composite. Its prime factorisation is
- 3
The divisors add up to 114048; without 80733 itself that is 33315, so 80733 is deficient (33315 is less than 80733). Euler's totient φ(80733) = 50624 numbers up to 80733 share no factor with it.
- 4
The digits of 80733 add up to 21, and repeating that until one digit is left gives the digital root 3. The Collatz sequence (halve if even, else 3n+1) takes 50 steps to reach 1.
LaTeX source of the formulas on this page
\[ 80733 = 3 \times 17 \times 1583 \]
80733 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 114048 |
| Euler totient φ(n) | 50624 |
| Square | 6517817289 |
| Cube | 526202943192837 |
| Square root | 284.135531 |
| Digit sum / digital root | 21 / 3 |
| Collatz steps to 1 | 50 |
| Scientific notation | 8.0733 × |
80733 in other forms
| Form | Value |
|---|---|
| In words | eighty thousand seven hundred and thirty-three |
| Binary (base 2) | 10011101101011101 |
| Octal (base 8) | 235535 |
| Hexadecimal (base 16) | 13B5D |
| Base 3 | 11002202010 |
| As time | 80733 seconds = 22 h 25 min 33 s |
Is 80733 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (80733 ÷ 3 = 26911) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 3) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 4) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 80733 a prime number?
No. 80733 = 3 × 17 × 1583, so it is divisible by 3.
What are the factors of 80733?
1, 3, 17, 51, 1583, 4749, 26911, 80733.
What is 80733 in binary?
10011101101011101 (hexadecimal 13B5D, octal 235535).
What is the square root of 80733?
About 284.1355.
Is 80733 divisible by 3?
Yes. Its digits add up to 21, a multiple of 3.
What is special about the number 80733?
It is a composite number with 8 divisors.