The number 80343
80343 is a composite number with 12 divisors. Its prime factorisation is × 79 × 113. Divisors (12): 1, 3, 9, 79, 113, 237, 339, 711, 1017, 8927, 26781, 80343.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
80343 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
80343 is composite. Its prime factorisation is
- 3
The divisors add up to 118560; without 80343 itself that is 38217, so 80343 is deficient (38217 is less than 80343). Euler's totient φ(80343) = 52416 numbers up to 80343 share no factor with it.
- 4
The digits of 80343 add up to 18, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 120 steps to reach 1.
LaTeX source of the formulas on this page
\[ 80343 = 3^{2} \times 79 \times 113 \]80343 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 118560 |
| Euler totient φ(n) | 52416 |
| Square | 6454997649 |
| Cube | 518613876113607 |
| Square root | 283.448408 (= 3√8927) |
| Digit sum / digital root | 18 / 9 |
| Collatz steps to 1 | 120 |
| Scientific notation | 8.0343 × |
80343 in other forms
| Form | Value |
|---|---|
| In words | eighty thousand three hundred and forty-three |
| Binary (base 2) | 10011100111010111 |
| Octal (base 8) | 234727 |
| Hexadecimal (base 16) | 139D7 |
| Base 3 | 11002012200 |
| As time | 80343 seconds = 22 h 19 min 3 s |
Is 80343 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (80343 ÷ 3 = 26781) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (80343 ÷ 9 = 8927) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 10) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 80343 a prime number?
No. 80343 = × 79 × 113, so it is divisible by 3.
What are the factors of 80343?
1, 3, 9, 79, 113, 237, 339, 711, 1017, 8927, 26781, 80343.
What is 80343 in binary?
10011100111010111 (hexadecimal 139D7, octal 234727).
What is the square root of 80343?
About 283.4484, exactly 3√8927.
Is 80343 divisible by 3?
Yes. Its digits add up to 18, a multiple of 3.
What is special about the number 80343?
It is a composite number with 12 divisors.