The number 80243
80243 is a composite number with 4 divisors. Its prime factorisation is 29 × 2767. Divisors (4): 1, 29, 2767, 80243.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 80243: a semiprime: 29 × 2767, the product of two primes.
- 2
80243 is composite. Its prime factorisation is
- 3
The divisors add up to 83040; without 80243 itself that is 2797, so 80243 is deficient (2797 is less than 80243). Euler's totient φ(80243) = 77448 numbers up to 80243 share no factor with it.
- 4
The digits of 80243 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 50 steps to reach 1.
LaTeX source of the formulas on this page
\[ 80243 = 29 \times 2767 \]
80243 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 83040 |
| Euler totient φ(n) | 77448 |
| Square | 6438939049 |
| Cube | 516679786108907 |
| Square root | 283.271954 |
| Digit sum / digital root | 17 / 8 |
| Collatz steps to 1 | 50 |
| Scientific notation | 8.0243 × |
80243 in other forms
| Form | Value |
|---|---|
| In words | eighty thousand two hundred and forty-three |
| Binary (base 2) | 10011100101110011 |
| Octal (base 8) | 234563 |
| Hexadecimal (base 16) | 13973 |
| Base 3 | 11002001222 |
| As time | 80243 seconds = 22 h 17 min 23 s |
Is 80243 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 9) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 11) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 80243 a prime number?
No. 80243 = 29 × 2767, so it is divisible by 29.
What are the factors of 80243?
1, 29, 2767, 80243.
What is 80243 in binary?
10011100101110011 (hexadecimal 13973, octal 234563).
What is the square root of 80243?
About 283.2720.
Is 80243 divisible by 3?
No. Its digits add up to 17, which is not a multiple of 3.
What is special about the number 80243?
80243 is a semiprime: 29 × 2767, the product of two primes.