The number 80323
80323 is a composite number with 4 divisors. Its prime factorisation is 47 × 1709. Divisors (4): 1, 47, 1709, 80323.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 80323: a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 47 × 1709, the product of two primes.
- 2
80323 is composite. Its prime factorisation is
- 3
The divisors add up to 82080; without 80323 itself that is 1757, so 80323 is deficient (1757 is less than 80323). Euler's totient φ(80323) = 78568 numbers up to 80323 share no factor with it.
- 4
The digits of 80323 add up to 16, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 68 steps to reach 1.
LaTeX source of the formulas on this page
\[ 80323 = 47 \times 1709 \]
80323 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 82080 |
| Euler totient φ(n) | 78568 |
| Square | 6451784329 |
| Cube | 518226672658267 |
| Square root | 283.413126 |
| Digit sum / digital root | 16 / 7 |
| Collatz steps to 1 | 68 |
| Scientific notation | 8.0323 × |
80323 in other forms
| Form | Value |
|---|---|
| In words | eighty thousand three hundred and twenty-three |
| Binary (base 2) | 10011100111000011 |
| Octal (base 8) | 234703 |
| Hexadecimal (base 16) | 139C3 |
| Base 3 | 11002011221 |
| As time | 80323 seconds = 22 h 18 min 43 s |
Is 80323 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 80323 a prime number?
No. 80323 = 47 × 1709, so it is divisible by 47.
What are the factors of 80323?
1, 47, 1709, 80323.
What is 80323 in binary?
10011100111000011 (hexadecimal 139C3, octal 234703).
What is the square root of 80323?
About 283.4131.
Is 80323 divisible by 3?
No. Its digits add up to 16, which is not a multiple of 3.
What is special about the number 80323?
80323 is a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 47 × 1709, the product of two primes.