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The number 80223

80223 is a composite number with 24 divisors. Its prime factorisation is 3 × 11211^{2} × 13 × 17. Divisors (24): 1, 3, 11, 13, 17, 33, 39, 51, 121, 143, 187, 221, 363, 429, 561, 663 … 80223.

Number

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How to work it out

  1. 1

    80223 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    80223 is composite. Its prime factorisation is

    80223=3×112×13×1780223 = 3 \times 11^{2} \times 13 \times 17
  3. 3

    The divisors add up to 134064; without 80223 itself that is 53841, so 80223 is deficient (53841 is less than 80223). Euler's totient φ(80223) = 42240 numbers up to 80223 share no factor with it.

  4. 4

    The digits of 80223 add up to 15, and repeating that until one digit is left gives the digital root 6. The Collatz sequence (halve if even, else 3n+1) takes 257 steps to reach 1.

LaTeX source of the formulas on this page
\[ 80223 = 3 \times 11^{2} \times 13 \times 17 \]

80223 at a glance

PropertyValue
Typecomposite
Number of divisors24
Sum of divisors134064
Euler totient φ(n)42240
Square6435729729
Cube516293546049567
Square root283.236650 (= 11√663)
Digit sum / digital root15 / 6
Collatz steps to 1257
Scientific notation8.0223 × 10410^{4}

80223 in other forms

FormValue
In wordseighty thousand two hundred and twenty-three
Binary (base 2)10011100101011111
Octal (base 8)234537
Hexadecimal (base 16)1395F
Base 311002001020
As time80223 seconds = 22 h 17 min 3 s

Is 80223 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (80223 ÷ 3 = 26741)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 3)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 6)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11Yes (80223 ÷ 11 = 7293)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 3)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 80223 a prime number?

No. 80223 = 3 × 11211^{2} × 13 × 17, so it is divisible by 3.

What are the factors of 80223?

1, 3, 11, 13, 17, 33, 39, 51, 121, 143, 187, 221, 363, 429, 561, 663, 1573, 2057, 2431, 4719, 6171, 7293, 26741, 80223.

What is 80223 in binary?

10011100101011111 (hexadecimal 1395F, octal 234537).

What is the square root of 80223?

About 283.2367, exactly 11√663.

Is 80223 divisible by 3?

Yes. Its digits add up to 15, a multiple of 3.

What is special about the number 80223?

It is a composite number with 24 divisors.

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    80223: is it prime? Factors, square root, binary, Roman numeral | WordGPT