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The number 65008

65008 is a composite number with 20 divisors. Its prime factorisation is 242^{4} × 17 × 239. Divisors (20): 1, 2, 4, 8, 16, 17, 34, 68, 136, 239, 272, 478, 956, 1912, 3824, 4063 … 65008.

Number

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How to work it out

  1. 1

    65008 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    65008 is composite. Its prime factorisation is

    65008=24×17×23965008 = 2^{4} \times 17 \times 239
  3. 3

    The divisors add up to 133920; without 65008 itself that is 68912, so 65008 is abundant (68912 is more than 65008). Euler's totient φ(65008) = 30464 numbers up to 65008 share no factor with it.

  4. 4

    The digits of 65008 add up to 19, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 68 steps to reach 1.

LaTeX source of the formulas on this page
\[ 65008 = 2^{4} \times 17 \times 239 \]

65008 at a glance

PropertyValue
Typecomposite
Number of divisors20
Sum of divisors133920
Euler totient φ(n)30464
Square4226040064
Cube274726412480512
Square root254.966664 (= 4√4063)
Digit sum / digital root19 / 1
Collatz steps to 168
Scientific notation6.5008 × 10410^{4}

65008 in other forms

FormValue
In wordssixty-five thousand and eight
Binary (base 2)1111110111110000
Octal (base 8)176760
Hexadecimal (base 16)FDF0
Base 310022011201
As time65008 seconds = 18 h 3 min 28 s

Is 65008 divisible by 2 to 12?

DivisorAnswerRule
2Yes (65008 ÷ 2 = 32504)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4Yes (65008 ÷ 4 = 16252)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 4)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 6)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8Yes (65008 ÷ 8 = 8126)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 1)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 8)A number is divisible by 10 if the last digit is 0.
11No (remainder 9)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 4)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 65008 a prime number?

No. 65008 = 242^{4} × 17 × 239, so it is divisible by 2.

What are the factors of 65008?

1, 2, 4, 8, 16, 17, 34, 68, 136, 239, 272, 478, 956, 1912, 3824, 4063, 8126, 16252, 32504, 65008.

What is 65008 in binary?

1111110111110000 (hexadecimal FDF0, octal 176760).

What is the square root of 65008?

About 254.9667, exactly 4√4063.

Is 65008 divisible by 3?

No. Its digits add up to 19, which is not a multiple of 3.

What is special about the number 65008?

It is a composite number with 20 divisors.

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