The number 65007
65007 is a composite number with 12 divisors. Its prime factorisation is × 31 × 233. Divisors (12): 1, 3, 9, 31, 93, 233, 279, 699, 2097, 7223, 21669, 65007.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
65007 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
65007 is composite. Its prime factorisation is
- 3
The divisors add up to 97344; without 65007 itself that is 32337, so 65007 is deficient (32337 is less than 65007). Euler's totient φ(65007) = 41760 numbers up to 65007 share no factor with it.
- 4
The digits of 65007 add up to 18, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 86 steps to reach 1.
LaTeX source of the formulas on this page
\[ 65007 = 3^{2} \times 31 \times 233 \]65007 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 97344 |
| Euler totient φ(n) | 41760 |
| Square | 4225910049 |
| Cube | 274713734555343 |
| Square root | 254.964703 (= 3√7223) |
| Digit sum / digital root | 18 / 9 |
| Collatz steps to 1 | 86 |
| Scientific notation | 6.5007 × |
65007 in other forms
| Form | Value |
|---|---|
| In words | sixty-five thousand and seven |
| Binary (base 2) | 1111110111101111 |
| Octal (base 8) | 176757 |
| Hexadecimal (base 16) | FDEF |
| Base 3 | 10022011200 |
| As time | 65007 seconds = 18 h 3 min 27 s |
Is 65007 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (65007 ÷ 3 = 21669) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (65007 ÷ 9 = 7223) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 8) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 65007 a prime number?
No. 65007 = × 31 × 233, so it is divisible by 3.
What are the factors of 65007?
1, 3, 9, 31, 93, 233, 279, 699, 2097, 7223, 21669, 65007.
What is 65007 in binary?
1111110111101111 (hexadecimal FDEF, octal 176757).
What is the square root of 65007?
About 254.9647, exactly 3√7223.
Is 65007 divisible by 3?
Yes. Its digits add up to 18, a multiple of 3.
What is special about the number 65007?
It is a composite number with 12 divisors.