The number 61983
61983 is a composite number with 12 divisors. Its prime factorisation is × 71 × 97. Divisors (12): 1, 3, 9, 71, 97, 213, 291, 639, 873, 6887, 20661, 61983.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
61983 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
61983 is composite. Its prime factorisation is
- 3
The divisors add up to 91728; without 61983 itself that is 29745, so 61983 is deficient (29745 is less than 61983). Euler's totient φ(61983) = 40320 numbers up to 61983 share no factor with it.
- 4
The digits of 61983 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 210 steps to reach 1.
LaTeX source of the formulas on this page
\[ 61983 = 3^{2} \times 71 \times 97 \]61983 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 91728 |
| Euler totient φ(n) | 40320 |
| Square | 3841892289 |
| Cube | 238132009749087 |
| Square root | 248.963853 (= 3√6887) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 210 |
| Scientific notation | 6.1983 × |
61983 in other forms
| Form | Value |
|---|---|
| In words | sixty-one thousand nine hundred and eighty-three |
| Binary (base 2) | 1111001000011111 |
| Octal (base 8) | 171037 |
| Hexadecimal (base 16) | F21F |
| Base 3 | 10011000200 |
| As time | 61983 seconds = 17 h 13 min 3 s |
Is 61983 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (61983 ÷ 3 = 20661) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (61983 ÷ 9 = 6887) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 9) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 61983 a prime number?
No. 61983 = × 71 × 97, so it is divisible by 3.
What are the factors of 61983?
1, 3, 9, 71, 97, 213, 291, 639, 873, 6887, 20661, 61983.
What is 61983 in binary?
1111001000011111 (hexadecimal F21F, octal 171037).
What is the square root of 61983?
About 248.9639, exactly 3√6887.
Is 61983 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 61983?
It is a composite number with 12 divisors.