WordGPT

The number 62001

62001 is a perfect square (249²). Its prime factorisation is 323^{2} × 83283^{2}. Divisors (9): 1, 3, 9, 83, 249, 747, 6889, 20667, 62001.

Number

Pick any whole number from 1 to 100,000.

How to work it out

  1. 1

    What is special about 62001: a perfect square (249²); a Harshad number: divisible by its digit sum 9.

  2. 2

    62001 is composite. Its prime factorisation is

    62001=32×83262001 = 3^{2} \times 83^{2}
  3. 3

    The divisors add up to 90649; without 62001 itself that is 28648, so 62001 is deficient (28648 is less than 62001). Euler's totient φ(62001) = 40836 numbers up to 62001 share no factor with it.

  4. 4

    The digits of 62001 add up to 9, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 179 steps to reach 1.

LaTeX source of the formulas on this page
\[ 62001 = 3^{2} \times 83^{2} \]

62001 at a glance

PropertyValue
Typecomposite
Number of divisors9
Sum of divisors90649
Euler totient φ(n)40836
Square3844124001
Cube238339532186001
Square root249
Digit sum / digital root9 / 9
Collatz steps to 1179
Scientific notation6.2001 × 10410^{4}
Perfect power2492249^{2}

62001 in other forms

FormValue
In wordssixty-two thousand and one
Binary (base 2)1111001000110001
Octal (base 8)171061
Hexadecimal (base 16)F231
Base 310011001100
As time62001 seconds = 17 h 13 min 21 s

Is 62001 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (62001 ÷ 3 = 20667)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 1)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 2)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9Yes (62001 ÷ 9 = 6889)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 1)A number is divisible by 10 if the last digit is 0.
11No (remainder 5)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 9)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 62001 a prime number?

No. 62001 = 323^{2} × 83283^{2}, so it is divisible by 3.

What are the factors of 62001?

1, 3, 9, 83, 249, 747, 6889, 20667, 62001.

What is 62001 in binary?

1111001000110001 (hexadecimal F231, octal 171061).

What is the square root of 62001?

249, because 249 × 249 = 62001.

Is 62001 divisible by 3?

Yes. Its digits add up to 9, a multiple of 3.

What is special about the number 62001?

62001 is a perfect square (249²); a Harshad number: divisible by its digit sum 9.

Find the next one

Nearby numbers

    62001: is it prime? Factors, square root, binary, Roman numeral | WordGPT