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The number 61924

61924 is a composite number with 12 divisors. Its prime factorisation is 222^{2} × 113 × 137. Divisors (12): 1, 2, 4, 113, 137, 226, 274, 452, 548, 15481, 30962, 61924.

Number

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How to work it out

  1. 1

    61924 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    61924 is composite. Its prime factorisation is

    61924=22×113×13761924 = 2^{2} \times 113 \times 137
  3. 3

    The divisors add up to 110124; without 61924 itself that is 48200, so 61924 is deficient (48200 is less than 61924). Euler's totient φ(61924) = 30464 numbers up to 61924 share no factor with it.

  4. 4

    The digits of 61924 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 148 steps to reach 1.

LaTeX source of the formulas on this page
\[ 61924 = 2^{2} \times 113 \times 137 \]

61924 at a glance

PropertyValue
Typecomposite
Number of divisors12
Sum of divisors110124
Euler totient φ(n)30464
Square3834581776
Cube237452641897024
Square root248.845333 (= 2√15481)
Digit sum / digital root22 / 4
Collatz steps to 1148
Scientific notation6.1924 × 10410^{4}

61924 in other forms

FormValue
In wordssixty-one thousand nine hundred and twenty-four
Binary (base 2)1111000111100100
Octal (base 8)170744
Hexadecimal (base 16)F1E4
Base 310010221111
As time61924 seconds = 17 h 12 min 4 s

Is 61924 divisible by 2 to 12?

DivisorAnswerRule
2Yes (61924 ÷ 2 = 30962)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4Yes (61924 ÷ 4 = 15481)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 4)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 4)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 2)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 4)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 4)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 4)A number is divisible by 10 if the last digit is 0.
11No (remainder 5)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 4)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 61924 a prime number?

No. 61924 = 222^{2} × 113 × 137, so it is divisible by 2.

What are the factors of 61924?

1, 2, 4, 113, 137, 226, 274, 452, 548, 15481, 30962, 61924.

What is 61924 in binary?

1111000111100100 (hexadecimal F1E4, octal 170744).

What is the square root of 61924?

About 248.8453, exactly 2√15481.

Is 61924 divisible by 3?

No. Its digits add up to 22, which is not a multiple of 3.

What is special about the number 61924?

It is a composite number with 12 divisors.

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