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The number 61421

61421 is a composite number with 4 divisors. Its prime factorisation is 17 × 3613. Divisors (4): 1, 17, 3613, 61421.

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How to work it out

  1. 1

    What is special about 61421: a semiprime: 17 × 3613, the product of two primes.

  2. 2

    61421 is composite. Its prime factorisation is

    61421=17×361361421 = 17 \times 3613
  3. 3

    The divisors add up to 65052; without 61421 itself that is 3631, so 61421 is deficient (3631 is less than 61421). Euler's totient φ(61421) = 57792 numbers up to 61421 share no factor with it.

  4. 4

    The digits of 61421 add up to 14, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 135 steps to reach 1.

LaTeX source of the formulas on this page
\[ 61421 = 17 \times 3613 \]

61421 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors65052
Euler totient φ(n)57792
Square3772539241
Cube231713132721461
Square root247.832605
Digit sum / digital root14 / 5
Collatz steps to 1135
Scientific notation6.1421 × 10410^{4}

61421 in other forms

FormValue
In wordssixty-one thousand four hundred and twenty-one
Binary (base 2)1110111111101101
Octal (base 8)167755
Hexadecimal (base 16)EFED
Base 310010020212
As time61421 seconds = 17 h 3 min 41 s

Is 61421 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 1)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 3)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 5)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 5)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 1)A number is divisible by 10 if the last digit is 0.
11No (remainder 8)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 5)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 61421 a prime number?

No. 61421 = 17 × 3613, so it is divisible by 17.

What are the factors of 61421?

1, 17, 3613, 61421.

What is 61421 in binary?

1110111111101101 (hexadecimal EFED, octal 167755).

What is the square root of 61421?

About 247.8326.

Is 61421 divisible by 3?

No. Its digits add up to 14, which is not a multiple of 3.

What is special about the number 61421?

61421 is a semiprime: 17 × 3613, the product of two primes.

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