The number 61321
61321 is a composite number with 8 divisors. Its prime factorisation is 13 × 53 × 89. Divisors (8): 1, 13, 53, 89, 689, 1157, 4717, 61321.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 61321: a Harshad number: divisible by its digit sum 13.
- 2
61321 is composite. Its prime factorisation is
- 3
The divisors add up to 68040; without 61321 itself that is 6719, so 61321 is deficient (6719 is less than 61321). Euler's totient φ(61321) = 54912 numbers up to 61321 share no factor with it.
- 4
The digits of 61321 add up to 13, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 148 steps to reach 1.
LaTeX source of the formulas on this page
\[ 61321 = 13 \times 53 \times 89 \]
61321 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 68040 |
| Euler totient φ(n) | 54912 |
| Square | 3760265041 |
| Cube | 230583212579161 |
| Square root | 247.630774 |
| Digit sum / digital root | 13 / 4 |
| Collatz steps to 1 | 148 |
| Scientific notation | 6.1321 × |
61321 in other forms
| Form | Value |
|---|---|
| In words | sixty-one thousand three hundred and twenty-one |
| Binary (base 2) | 1110111110001001 |
| Octal (base 8) | 167611 |
| Hexadecimal (base 16) | EF89 |
| Base 3 | 10010010011 |
| As time | 61321 seconds = 17 h 2 min 1 s |
Is 61321 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 7) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 61321 a prime number?
No. 61321 = 13 × 53 × 89, so it is divisible by 13.
What are the factors of 61321?
1, 13, 53, 89, 689, 1157, 4717, 61321.
What is 61321 in binary?
1110111110001001 (hexadecimal EF89, octal 167611).
What is the square root of 61321?
About 247.6308.
Is 61321 divisible by 3?
No. Its digits add up to 13, which is not a multiple of 3.
What is special about the number 61321?
61321 is a Harshad number: divisible by its digit sum 13.