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The number 60003

60003 is a composite number with 12 divisors. Its prime factorisation is 323^{2} × 59 × 113. Divisors (12): 1, 3, 9, 59, 113, 177, 339, 531, 1017, 6667, 20001, 60003.

Number

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How to work it out

  1. 1

    What is special about 60003: a Harshad number: divisible by its digit sum 9.

  2. 2

    60003 is composite. Its prime factorisation is

    60003=32×59×11360003 = 3^{2} \times 59 \times 113
  3. 3

    The divisors add up to 88920; without 60003 itself that is 28917, so 60003 is deficient (28917 is less than 60003). Euler's totient φ(60003) = 38976 numbers up to 60003 share no factor with it.

  4. 4

    The digits of 60003 add up to 9, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 166 steps to reach 1.

LaTeX source of the formulas on this page
\[ 60003 = 3^{2} \times 59 \times 113 \]

60003 at a glance

PropertyValue
Typecomposite
Number of divisors12
Sum of divisors88920
Euler totient φ(n)38976
Square3600360009
Cube216032401620027
Square root244.955098 (= 3√6667)
Digit sum / digital root9 / 9
Collatz steps to 1166
Scientific notation6.0003 × 10410^{4}

60003 in other forms

FormValue
In wordssixty thousand and three
Binary (base 2)1110101001100011
Octal (base 8)165143
Hexadecimal (base 16)EA63
Base 310001022100
As time60003 seconds = 16 h 40 min 3 s

Is 60003 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (60003 ÷ 3 = 20001)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 6)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 3)A number is divisible by 8 if the last three digits make a multiple of 8.
9Yes (60003 ÷ 9 = 6667)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 9)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 3)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 60003 a prime number?

No. 60003 = 323^{2} × 59 × 113, so it is divisible by 3.

What are the factors of 60003?

1, 3, 9, 59, 113, 177, 339, 531, 1017, 6667, 20001, 60003.

What is 60003 in binary?

1110101001100011 (hexadecimal EA63, octal 165143).

What is the square root of 60003?

About 244.9551, exactly 3√6667.

Is 60003 divisible by 3?

Yes. Its digits add up to 9, a multiple of 3.

What is special about the number 60003?

60003 is a Harshad number: divisible by its digit sum 9.

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    60003: is it prime? Factors, square root, binary, Roman numeral | WordGPT