The number 59993
59993 is a composite number with 4 divisors. Its prime factorisation is 17 × 3529. Divisors (4): 1, 17, 3529, 59993.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 59993: a semiprime: 17 × 3529, the product of two primes.
- 2
59993 is composite. Its prime factorisation is
- 3
The divisors add up to 63540; without 59993 itself that is 3547, so 59993 is deficient (3547 is less than 59993). Euler's totient φ(59993) = 56448 numbers up to 59993 share no factor with it.
- 4
The digits of 59993 add up to 35, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 65 steps to reach 1.
LaTeX source of the formulas on this page
\[ 59993 = 17 \times 3529 \]
59993 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 63540 |
| Euler totient φ(n) | 56448 |
| Square | 3599160049 |
| Cube | 215924408819657 |
| Square root | 244.934685 |
| Digit sum / digital root | 35 / 8 |
| Collatz steps to 1 | 65 |
| Scientific notation | 5.9993 × |
59993 in other forms
| Form | Value |
|---|---|
| In words | fifty-nine thousand nine hundred and ninety-three |
| Binary (base 2) | 1110101001011001 |
| Octal (base 8) | 165131 |
| Hexadecimal (base 16) | EA59 |
| Base 3 | 10001021222 |
| As time | 59993 seconds = 16 h 39 min 53 s |
Is 59993 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 10) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 59993 a prime number?
No. 59993 = 17 × 3529, so it is divisible by 17.
What are the factors of 59993?
1, 17, 3529, 59993.
What is 59993 in binary?
1110101001011001 (hexadecimal EA59, octal 165131).
What is the square root of 59993?
About 244.9347.
Is 59993 divisible by 3?
No. Its digits add up to 35, which is not a multiple of 3.
What is special about the number 59993?
59993 is a semiprime: 17 × 3529, the product of two primes.