The number 5887
5887 is a composite number with 6 divisors. Its prime factorisation is 7 Ć . Divisors (6): 1, 7, 29, 203, 841, 5887.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
5887 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
5887 is composite. Its prime factorisation is
- 3
The divisors add up to 6968; without 5887 itself that is 1081, so 5887 is deficient (1081 is less than 5887). Euler's totient Ļ(5887) = 4872 numbers up to 5887 share no factor with it.
- 4
The digits of 5887 add up to 28, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 124 steps to reach 1.
LaTeX source of the formulas on this page
\[ 5887 = 7 \times 29^{2} \]5887 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 6 |
| Sum of divisors | 6968 |
| Euler totient Ļ(n) | 4872 |
| Square | 34656769 |
| Cube | 204024399103 |
| Square root | 76.726788 (= 29ā7) |
| Digit sum / digital root | 28 / 1 |
| Collatz steps to 1 | 124 |
| Scientific notation | 5.887 Ć |
5887 in other forms
| Form | Value |
|---|---|
| In words | five thousand eight hundred and eighty-seven |
| Binary (base 2) | 1011011111111 |
| Octal (base 8) | 13377 |
| Hexadecimal (base 16) | 16FF |
| Base 3 | 22002001 |
| As time | 5887 seconds = 1 h 38 min 7 s |
Is 5887 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (5887 Ć· 7 = 841) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 1) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 5887 a prime number?
No. 5887 = 7 Ć , so it is divisible by 7.
What are the factors of 5887?
1, 7, 29, 203, 841, 5887.
What is 5887 in binary?
1011011111111 (hexadecimal 16FF, octal 13377).
What is the square root of 5887?
About 76.7268, exactly 29ā7.
Is 5887 divisible by 3?
No. Its digits add up to 28, which is not a multiple of 3.
What is special about the number 5887?
It is a composite number with 6 divisors.