The number 5787
5787 is a composite number with 6 divisors. Its prime factorisation is × 643. Divisors (6): 1, 3, 9, 643, 1929, 5787.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
5787 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
5787 is composite. Its prime factorisation is
- 3
The divisors add up to 8372; without 5787 itself that is 2585, so 5787 is deficient (2585 is less than 5787). Euler's totient φ(5787) = 3852 numbers up to 5787 share no factor with it.
- 4
The digits of 5787 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 80 steps to reach 1.
LaTeX source of the formulas on this page
\[ 5787 = 3^{2} \times 643 \]5787 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 6 |
| Sum of divisors | 8372 |
| Euler totient φ(n) | 3852 |
| Square | 33489369 |
| Cube | 193802978403 |
| Square root | 76.072334 (= 3√643) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 80 |
| Scientific notation | 5.787 × |
5787 in other forms
| Form | Value |
|---|---|
| In words | five thousand seven hundred and eighty-seven |
| Binary (base 2) | 1011010011011 |
| Octal (base 8) | 13233 |
| Hexadecimal (base 16) | 169B |
| Base 3 | 21221100 |
| As time | 5787 seconds = 1 h 36 min 27 s |
Is 5787 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (5787 ÷ 3 = 1929) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (5787 ÷ 9 = 643) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 5787 a prime number?
No. 5787 = × 643, so it is divisible by 3.
What are the factors of 5787?
1, 3, 9, 643, 1929, 5787.
What is 5787 in binary?
1011010011011 (hexadecimal 169B, octal 13233).
What is the square root of 5787?
About 76.0723, exactly 3√643.
Is 5787 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 5787?
It is a composite number with 6 divisors.