The number 58121
58121 is a composite number with 12 divisors. Its prime factorisation is 7 × × 23. Divisors (12): 1, 7, 19, 23, 133, 161, 361, 437, 2527, 3059, 8303, 58121.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
58121 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
58121 is composite. Its prime factorisation is
- 3
The divisors add up to 73152; without 58121 itself that is 15031, so 58121 is deficient (15031 is less than 58121). Euler's totient φ(58121) = 45144 numbers up to 58121 share no factor with it.
- 4
The digits of 58121 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 166 steps to reach 1.
LaTeX source of the formulas on this page
\[ 58121 = 7 \times 19^{2} \times 23 \]58121 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 73152 |
| Euler totient φ(n) | 45144 |
| Square | 3378050641 |
| Cube | 196335681305561 |
| Square root | 241.082973 (= 19√161) |
| Digit sum / digital root | 17 / 8 |
| Collatz steps to 1 | 166 |
| Scientific notation | 5.8121 × |
58121 in other forms
| Form | Value |
|---|---|
| In words | fifty-eight thousand one hundred and twenty-one |
| Binary (base 2) | 1110001100001001 |
| Octal (base 8) | 161411 |
| Hexadecimal (base 16) | E309 |
| Base 3 | 2221201122 |
| As time | 58121 seconds = 16 h 8 min 41 s |
Is 58121 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (58121 ÷ 7 = 8303) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 8) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 58121 a prime number?
No. 58121 = 7 × × 23, so it is divisible by 7.
What are the factors of 58121?
1, 7, 19, 23, 133, 161, 361, 437, 2527, 3059, 8303, 58121.
What is 58121 in binary?
1110001100001001 (hexadecimal E309, octal 161411).
What is the square root of 58121?
About 241.0830, exactly 19√161.
Is 58121 divisible by 3?
No. Its digits add up to 17, which is not a multiple of 3.
What is special about the number 58121?
It is a composite number with 12 divisors.