The number 58021
58021 is a composite number with 4 divisors. Its prime factorisation is 17 × 3413. Divisors (4): 1, 17, 3413, 58021.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 58021: a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 17 × 3413, the product of two primes.
- 2
58021 is composite. Its prime factorisation is
- 3
The divisors add up to 61452; without 58021 itself that is 3431, so 58021 is deficient (3431 is less than 58021). Euler's totient φ(58021) = 54592 numbers up to 58021 share no factor with it.
- 4
The digits of 58021 add up to 16, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 135 steps to reach 1.
LaTeX source of the formulas on this page
\[ 58021 = 17 \times 3413 \]
58021 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 61452 |
| Euler totient φ(n) | 54592 |
| Square | 3366436441 |
| Cube | 195324008743261 |
| Square root | 240.875487 |
| Digit sum / digital root | 16 / 7 |
| Collatz steps to 1 | 135 |
| Scientific notation | 5.8021 × |
58021 in other forms
| Form | Value |
|---|---|
| In words | fifty-eight thousand and twenty-one |
| Binary (base 2) | 1110001010100101 |
| Octal (base 8) | 161245 |
| Hexadecimal (base 16) | E2A5 |
| Base 3 | 2221120221 |
| As time | 58021 seconds = 16 h 7 min 1 s |
Is 58021 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 7) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 58021 a prime number?
No. 58021 = 17 × 3413, so it is divisible by 17.
What are the factors of 58021?
1, 17, 3413, 58021.
What is 58021 in binary?
1110001010100101 (hexadecimal E2A5, octal 161245).
What is the square root of 58021?
About 240.8755.
Is 58021 divisible by 3?
No. Its digits add up to 16, which is not a multiple of 3.
What is special about the number 58021?
58021 is a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 17 × 3413, the product of two primes.