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The number 53713

53713 is a composite number with 8 divisors. Its prime factorisation is 11 × 19 × 257. Divisors (8): 1, 11, 19, 209, 257, 2827, 4883, 53713.

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How to work it out

  1. 1

    What is special about 53713: a Harshad number: divisible by its digit sum 19.

  2. 2

    53713 is composite. Its prime factorisation is

    53713=11×19×25753713 = 11 \times 19 \times 257
  3. 3

    The divisors add up to 61920; without 53713 itself that is 8207, so 53713 is deficient (8207 is less than 53713). Euler's totient φ(53713) = 46080 numbers up to 53713 share no factor with it.

  4. 4

    The digits of 53713 add up to 19, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 140 steps to reach 1.

LaTeX source of the formulas on this page
\[ 53713 = 11 \times 19 \times 257 \]

53713 at a glance

PropertyValue
Typecomposite
Number of divisors8
Sum of divisors61920
Euler totient φ(n)46080
Square2885086369
Cube154966644138097
Square root231.760652
Digit sum / digital root19 / 1
Collatz steps to 1140
Scientific notation5.3713 × 10410^{4}

53713 in other forms

FormValue
In wordsfifty-three thousand seven hundred and thirteen
Binary (base 2)1101000111010001
Octal (base 8)150721
Hexadecimal (base 16)D1D1
Base 32201200101
As time53713 seconds = 14 h 55 min 13 s

Is 53713 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 2)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 1)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11Yes (53713 ÷ 11 = 4883)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 1)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 53713 a prime number?

No. 53713 = 11 × 19 × 257, so it is divisible by 11.

What are the factors of 53713?

1, 11, 19, 209, 257, 2827, 4883, 53713.

What is 53713 in binary?

1101000111010001 (hexadecimal D1D1, octal 150721).

What is the square root of 53713?

About 231.7607.

Is 53713 divisible by 3?

No. Its digits add up to 19, which is not a multiple of 3.

What is special about the number 53713?

53713 is a Harshad number: divisible by its digit sum 19.

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    53713: is it prime? Factors, square root, binary, Roman numeral | WordGPT