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The number 53613

53613 is a composite number with 24 divisors. Its prime factorisation is 323^{2} × 7 × 23 × 37. Divisors (24): 1, 3, 7, 9, 21, 23, 37, 63, 69, 111, 161, 207, 259, 333, 483, 777 … 53613.

Number

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How to work it out

  1. 1

    53613 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    53613 is composite. Its prime factorisation is

    53613=32×7×23×3753613 = 3^{2} \times 7 \times 23 \times 37
  3. 3

    The divisors add up to 94848; without 53613 itself that is 41235, so 53613 is deficient (41235 is less than 53613). Euler's totient φ(53613) = 28512 numbers up to 53613 share no factor with it.

  4. 4

    The digits of 53613 add up to 18, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 109 steps to reach 1.

LaTeX source of the formulas on this page
\[ 53613 = 3^{2} \times 7 \times 23 \times 37 \]

53613 at a glance

PropertyValue
Typecomposite
Number of divisors24
Sum of divisors94848
Euler totient φ(n)28512
Square2874353769
Cube154102728617397
Square root231.544812 (= 3√5957)
Digit sum / digital root18 / 9
Collatz steps to 1109
Scientific notation5.3613 × 10410^{4}

53613 in other forms

FormValue
In wordsfifty-three thousand six hundred and thirteen
Binary (base 2)1101000101101101
Octal (base 8)150555
Hexadecimal (base 16)D16D
Base 32201112200
As time53613 seconds = 14 h 53 min 33 s

Is 53613 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (53613 ÷ 3 = 17871)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7Yes (53613 ÷ 7 = 7659)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 5)A number is divisible by 8 if the last three digits make a multiple of 8.
9Yes (53613 ÷ 9 = 5957)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 10)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 9)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 53613 a prime number?

No. 53613 = 323^{2} × 7 × 23 × 37, so it is divisible by 3.

What are the factors of 53613?

1, 3, 7, 9, 21, 23, 37, 63, 69, 111, 161, 207, 259, 333, 483, 777, 851, 1449, 2331, 2553, 5957, 7659, 17871, 53613.

What is 53613 in binary?

1101000101101101 (hexadecimal D16D, octal 150555).

What is the square root of 53613?

About 231.5448, exactly 3√5957.

Is 53613 divisible by 3?

Yes. Its digits add up to 18, a multiple of 3.

What is special about the number 53613?

It is a composite number with 24 divisors.

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    53613: is it prime? Factors, square root, binary, Roman numeral | WordGPT