The number 49935
49935 is a composite number with 8 divisors. Its prime factorisation is 3 × 5 × 3329. Divisors (8): 1, 3, 5, 15, 3329, 9987, 16645, 49935.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
49935 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
49935 is composite. Its prime factorisation is
- 3
The divisors add up to 79920; without 49935 itself that is 29985, so 49935 is deficient (29985 is less than 49935). Euler's totient φ(49935) = 26624 numbers up to 49935 share no factor with it.
- 4
The digits of 49935 add up to 30, and repeating that until one digit is left gives the digital root 3. The Collatz sequence (halve if even, else 3n+1) takes 52 steps to reach 1.
LaTeX source of the formulas on this page
\[ 49935 = 3 \times 5 \times 3329 \]
49935 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 79920 |
| Euler totient φ(n) | 26624 |
| Square | 2493504225 |
| Cube | 124513133475375 |
| Square root | 223.461406 |
| Digit sum / digital root | 30 / 3 |
| Collatz steps to 1 | 52 |
| Scientific notation | 4.9935 × |
49935 in other forms
| Form | Value |
|---|---|
| In words | forty-nine thousand nine hundred and thirty-five |
| Binary (base 2) | 1100001100001111 |
| Octal (base 8) | 141417 |
| Hexadecimal (base 16) | C30F |
| Base 3 | 2112111110 |
| As time | 49935 seconds = 13 h 52 min 15 s |
Is 49935 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (49935 ÷ 3 = 16645) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | Yes (49935 ÷ 5 = 9987) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 3) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 5) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 49935 a prime number?
No. 49935 = 3 × 5 × 3329, so it is divisible by 3.
What are the factors of 49935?
1, 3, 5, 15, 3329, 9987, 16645, 49935.
What is 49935 in binary?
1100001100001111 (hexadecimal C30F, octal 141417).
What is the square root of 49935?
About 223.4614.
Is 49935 divisible by 3?
Yes. Its digits add up to 30, a multiple of 3.
What is special about the number 49935?
It is a composite number with 8 divisors.