The number 49925
49925 is a composite number with 6 divisors. Its prime factorisation is Ć 1997. Divisors (6): 1, 5, 25, 1997, 9985, 49925.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
49925 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
49925 is composite. Its prime factorisation is
- 3
The divisors add up to 61938; without 49925 itself that is 12013, so 49925 is deficient (12013 is less than 49925). Euler's totient Ļ(49925) = 39920 numbers up to 49925 share no factor with it.
- 4
The digits of 49925 add up to 29, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 52 steps to reach 1.
LaTeX source of the formulas on this page
\[ 49925 = 5^{2} \times 1997 \]49925 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 6 |
| Sum of divisors | 61938 |
| Euler totient Ļ(n) | 39920 |
| Square | 2492505625 |
| Cube | 124438343328125 |
| Square root | 223.439030 (= 5ā1997) |
| Digit sum / digital root | 29 / 2 |
| Collatz steps to 1 | 52 |
| Scientific notation | 4.9925 Ć |
49925 in other forms
| Form | Value |
|---|---|
| In words | forty-nine thousand nine hundred and twenty-five |
| Binary (base 2) | 1100001100000101 |
| Octal (base 8) | 141405 |
| Hexadecimal (base 16) | C305 |
| Base 3 | 2112111002 |
| As time | 49925 seconds = 13 h 52 min 5 s |
Is 49925 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | Yes (49925 Ć· 5 = 9985) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 5) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 7) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 49925 a prime number?
No. 49925 = Ć 1997, so it is divisible by 5.
What are the factors of 49925?
1, 5, 25, 1997, 9985, 49925.
What is 49925 in binary?
1100001100000101 (hexadecimal C305, octal 141405).
What is the square root of 49925?
About 223.4390, exactly 5ā1997.
Is 49925 divisible by 3?
No. Its digits add up to 29, which is not a multiple of 3.
What is special about the number 49925?
It is a composite number with 6 divisors.