The number 48423
48423 is a composite number with 4 divisors. Its prime factorisation is 3 × 16141. Divisors (4): 1, 3, 16141, 48423.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 48423: a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 3 × 16141, the product of two primes.
- 2
48423 is composite. Its prime factorisation is
- 3
The divisors add up to 64568; without 48423 itself that is 16145, so 48423 is deficient (16145 is less than 48423). Euler's totient φ(48423) = 32280 numbers up to 48423 share no factor with it.
- 4
The digits of 48423 add up to 21, and repeating that until one digit is left gives the digital root 3. The Collatz sequence (halve if even, else 3n+1) takes 52 steps to reach 1.
LaTeX source of the formulas on this page
\[ 48423 = 3 \times 16141 \]
48423 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 64568 |
| Euler totient φ(n) | 32280 |
| Square | 2344786929 |
| Cube | 113541617462967 |
| Square root | 220.052267 |
| Digit sum / digital root | 21 / 3 |
| Collatz steps to 1 | 52 |
| Scientific notation | 4.8423 × |
48423 in other forms
| Form | Value |
|---|---|
| In words | forty-eight thousand four hundred and twenty-three |
| Binary (base 2) | 1011110100100111 |
| Octal (base 8) | 136447 |
| Hexadecimal (base 16) | BD27 |
| Base 3 | 2110102110 |
| As time | 48423 seconds = 13 h 27 min 3 s |
Is 48423 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (48423 ÷ 3 = 16141) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 3) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 48423 a prime number?
No. 48423 = 3 × 16141, so it is divisible by 3.
What are the factors of 48423?
1, 3, 16141, 48423.
What is 48423 in binary?
1011110100100111 (hexadecimal BD27, octal 136447).
What is the square root of 48423?
About 220.0523.
Is 48423 divisible by 3?
Yes. Its digits add up to 21, a multiple of 3.
What is special about the number 48423?
48423 is a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 3 × 16141, the product of two primes.