The number 48841

No. 48841 = 13^2 × 17^2, so it is divisible by 13.

48841 is a perfect square (221²). Its prime factorisation is $13^{2}$ × $17^{2}$ . Divisors (9): 1, 13, 17, 169, 221, 289, 2873, 3757, 48841.

Number

Pick any whole number from 1 to 100,000.

48841 = 13^{2} \times 17^{2}

How to work it out

1
What is special about 48841: a perfect square (221²).
2
48841 is composite. Its prime factorisation is
$48841 = 13^{2} \times 17^{2}$
3
The divisors add up to 56181; without 48841 itself that is 7340, so 48841 is deficient (7340 is less than 48841). Euler's totient φ(48841) = 42432 numbers up to 48841 share no factor with it.
4
The digits of 48841 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 101 steps to reach 1.

LaTeX source of the formulas on this page

\[ 48841 = 13^{2} \times 17^{2} \]

Form	Value
In words	forty-eight thousand eight hundred and forty-one
Binary (base 2)	1011111011001001
Octal (base 8)	137311
Hexadecimal (base 16)	BEC9
Base 3	2110222221
As time	48841 seconds = 13 h 34 min 1 s

Divisor	Answer	Rule
2	No (remainder 1)	A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3	No (remainder 1)	A number is divisible by 3 if the digits add up to a multiple of 3.
4	No (remainder 1)	A number is divisible by 4 if the last two digits make a multiple of 4.
5	No (remainder 1)	A number is divisible by 5 if the last digit is 0 or 5.
6	No (remainder 1)	A number is divisible by 6 if it is divisible by both 2 and 3.
7	No (remainder 2)	A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8	No (remainder 1)	A number is divisible by 8 if the last three digits make a multiple of 8.
9	No (remainder 7)	A number is divisible by 9 if the digits add up to a multiple of 9.
10	No (remainder 1)	A number is divisible by 10 if the last digit is 0.
11	No (remainder 1)	A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12	No (remainder 1)	A number is divisible by 12 if it is divisible by both 3 and 4.

Is 48841 a prime number?

No. 48841 = $13^{2}$ × $17^{2}$ , so it is divisible by 13.

What are the factors of 48841?

1, 13, 17, 169, 221, 289, 2873, 3757, 48841.

What is 48841 in binary?

1011111011001001 (hexadecimal BEC9, octal 137311).

What is the square root of 48841?

221, because 221 × 221 = 48841.

Is 48841 divisible by 3?

No. Its digits add up to 25, which is not a multiple of 3.

What is special about the number 48841?

48841 is a perfect square (221²).