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The number 42993

42993 is a composite number with 12 divisors. Its prime factorisation is 323^{2} × 17 × 281. Divisors (12): 1, 3, 9, 17, 51, 153, 281, 843, 2529, 4777, 14331, 42993.

Number

Pick any whole number from 1 to 100,000.

How to work it out

  1. 1

    42993 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    42993 is composite. Its prime factorisation is

    42993=32×17×28142993 = 3^{2} \times 17 \times 281
  3. 3

    The divisors add up to 65988; without 42993 itself that is 22995, so 42993 is deficient (22995 is less than 42993). Euler's totient φ(42993) = 26880 numbers up to 42993 share no factor with it.

  4. 4

    The digits of 42993 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 101 steps to reach 1.

LaTeX source of the formulas on this page
\[ 42993 = 3^{2} \times 17 \times 281 \]

42993 at a glance

PropertyValue
Typecomposite
Number of divisors12
Sum of divisors65988
Euler totient φ(n)26880
Square1848398049
Cube79468177320657
Square root207.347534 (= 3√4777)
Digit sum / digital root27 / 9
Collatz steps to 1101
Scientific notation4.2993 × 10410^{4}

42993 in other forms

FormValue
In wordsforty-two thousand nine hundred and ninety-three
Binary (base 2)1010011111110001
Octal (base 8)123761
Hexadecimal (base 16)A7F1
Base 32011222100
As time42993 seconds = 11 h 56 min 33 s

Is 42993 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (42993 ÷ 3 = 14331)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 6)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9Yes (42993 ÷ 9 = 4777)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 5)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 9)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 42993 a prime number?

No. 42993 = 323^{2} × 17 × 281, so it is divisible by 3.

What are the factors of 42993?

1, 3, 9, 17, 51, 153, 281, 843, 2529, 4777, 14331, 42993.

What is 42993 in binary?

1010011111110001 (hexadecimal A7F1, octal 123761).

What is the square root of 42993?

About 207.3475, exactly 3√4777.

Is 42993 divisible by 3?

Yes. Its digits add up to 27, a multiple of 3.

What is special about the number 42993?

It is a composite number with 12 divisors.

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    42993: is it prime? Factors, square root, binary, Roman numeral | WordGPT