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The number 42893

42893 is a composite number with 4 divisors. Its prime factorisation is 59 × 727. Divisors (4): 1, 59, 727, 42893.

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How to work it out

  1. 1

    What is special about 42893: a semiprime: 59 × 727, the product of two primes.

  2. 2

    42893 is composite. Its prime factorisation is

    42893=59×72742893 = 59 \times 727
  3. 3

    The divisors add up to 43680; without 42893 itself that is 787, so 42893 is deficient (787 is less than 42893). Euler's totient φ(42893) = 42108 numbers up to 42893 share no factor with it.

  4. 4

    The digits of 42893 add up to 26, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 75 steps to reach 1.

LaTeX source of the formulas on this page
\[ 42893 = 59 \times 727 \]

42893 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors43680
Euler totient φ(n)42108
Square1839809449
Cube78914946695957
Square root207.106253
Digit sum / digital root26 / 8
Collatz steps to 175
Scientific notation4.2893 × 10410^{4}

42893 in other forms

FormValue
In wordsforty-two thousand eight hundred and ninety-three
Binary (base 2)1010011110001101
Octal (base 8)123615
Hexadecimal (base 16)A78D
Base 32011211122
As time42893 seconds = 11 h 54 min 53 s

Is 42893 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 4)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 5)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 8)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 4)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 5)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 42893 a prime number?

No. 42893 = 59 × 727, so it is divisible by 59.

What are the factors of 42893?

1, 59, 727, 42893.

What is 42893 in binary?

1010011110001101 (hexadecimal A78D, octal 123615).

What is the square root of 42893?

About 207.1063.

Is 42893 divisible by 3?

No. Its digits add up to 26, which is not a multiple of 3.

What is special about the number 42893?

42893 is a semiprime: 59 × 727, the product of two primes.

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