The number 40373
40373 is a composite number with 4 divisors. Its prime factorisation is 47 × 859. Divisors (4): 1, 47, 859, 40373.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 40373: a semiprime: 47 × 859, the product of two primes.
- 2
40373 is composite. Its prime factorisation is
- 3
The divisors add up to 41280; without 40373 itself that is 907, so 40373 is deficient (907 is less than 40373). Euler's totient φ(40373) = 39468 numbers up to 40373 share no factor with it.
- 4
The digits of 40373 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 137 steps to reach 1.
LaTeX source of the formulas on this page
\[ 40373 = 47 \times 859 \]
40373 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 41280 |
| Euler totient φ(n) | 39468 |
| Square | 1629979129 |
| Cube | 65807147375117 |
| Square root | 200.930336 |
| Digit sum / digital root | 17 / 8 |
| Collatz steps to 1 | 137 |
| Scientific notation | 4.0373 × |
40373 in other forms
| Form | Value |
|---|---|
| In words | forty thousand three hundred and seventy-three |
| Binary (base 2) | 1001110110110101 |
| Octal (base 8) | 116665 |
| Hexadecimal (base 16) | 9DB5 |
| Base 3 | 2001101022 |
| As time | 40373 seconds = 11 h 12 min 53 s |
Is 40373 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 40373 a prime number?
No. 40373 = 47 × 859, so it is divisible by 47.
What are the factors of 40373?
1, 47, 859, 40373.
What is 40373 in binary?
1001110110110101 (hexadecimal 9DB5, octal 116665).
What is the square root of 40373?
About 200.9303.
Is 40373 divisible by 3?
No. Its digits add up to 17, which is not a multiple of 3.
What is special about the number 40373?
40373 is a semiprime: 47 × 859, the product of two primes.