The number 40273
40273 is a composite number with 8 divisors. Its prime factorisation is 17 × 23 × 103. Divisors (8): 1, 17, 23, 103, 391, 1751, 2369, 40273.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
40273 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
40273 is composite. Its prime factorisation is
- 3
The divisors add up to 44928; without 40273 itself that is 4655, so 40273 is deficient (4655 is less than 40273). Euler's totient φ(40273) = 35904 numbers up to 40273 share no factor with it.
- 4
The digits of 40273 add up to 16, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 93 steps to reach 1.
LaTeX source of the formulas on this page
\[ 40273 = 17 \times 23 \times 103 \]
40273 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 44928 |
| Euler totient φ(n) | 35904 |
| Square | 1621914529 |
| Cube | 65319363826417 |
| Square root | 200.681339 |
| Digit sum / digital root | 16 / 7 |
| Collatz steps to 1 | 93 |
| Scientific notation | 4.0273 × |
40273 in other forms
| Form | Value |
|---|---|
| In words | forty thousand two hundred and seventy-three |
| Binary (base 2) | 1001110101010001 |
| Octal (base 8) | 116521 |
| Hexadecimal (base 16) | 9D51 |
| Base 3 | 2001020121 |
| As time | 40273 seconds = 11 h 11 min 13 s |
Is 40273 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 40273 a prime number?
No. 40273 = 17 × 23 × 103, so it is divisible by 17.
What are the factors of 40273?
1, 17, 23, 103, 391, 1751, 2369, 40273.
What is 40273 in binary?
1001110101010001 (hexadecimal 9D51, octal 116521).
What is the square root of 40273?
About 200.6813.
Is 40273 divisible by 3?
No. Its digits add up to 16, which is not a multiple of 3.
What is special about the number 40273?
It is a composite number with 8 divisors.