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The number 40003

40003 is a composite number with 4 divisors. Its prime factorisation is 109 × 367. Divisors (4): 1, 109, 367, 40003.

Number

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How to work it out

  1. 1

    What is special about 40003: a semiprime: 109 × 367, the product of two primes.

  2. 2

    40003 is composite. Its prime factorisation is

    40003=109×36740003 = 109 \times 367
  3. 3

    The divisors add up to 40480; without 40003 itself that is 477, so 40003 is deficient (477 is less than 40003). Euler's totient φ(40003) = 39528 numbers up to 40003 share no factor with it.

  4. 4

    The digits of 40003 add up to 7, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 168 steps to reach 1.

LaTeX source of the formulas on this page
\[ 40003 = 109 \times 367 \]

40003 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors40480
Euler totient φ(n)39528
Square1600240009
Cube64014401080027
Square root200.007500
Digit sum / digital root7 / 7
Collatz steps to 1168
Scientific notation4.0003 × 10410^{4}

40003 in other forms

FormValue
In wordsforty thousand and three
Binary (base 2)1001110001000011
Octal (base 8)116103
Hexadecimal (base 16)9C43
Base 32000212121
As time40003 seconds = 11 h 6 min 43 s

Is 40003 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 5)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 3)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 7)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 7)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 40003 a prime number?

No. 40003 = 109 × 367, so it is divisible by 109.

What are the factors of 40003?

1, 109, 367, 40003.

What is 40003 in binary?

1001110001000011 (hexadecimal 9C43, octal 116103).

What is the square root of 40003?

About 200.0075.

Is 40003 divisible by 3?

No. Its digits add up to 7, which is not a multiple of 3.

What is special about the number 40003?

40003 is a semiprime: 109 × 367, the product of two primes.

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