The number 39993
39993 is a palindrome: it reads 39993 backwards too and a binary palindrome (1001110000111001). Its prime factorisation is 3 × 13331. Divisors (4): 1, 3, 13331, 39993.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 39993: a palindrome: it reads 39993 backwards too; a binary palindrome (1001110000111001); a semiprime: 3 × 13331, the product of two primes.
- 2
39993 is composite. Its prime factorisation is
- 3
The divisors add up to 53328; without 39993 itself that is 13335, so 39993 is deficient (13335 is less than 39993). Euler's totient φ(39993) = 26660 numbers up to 39993 share no factor with it.
- 4
The digits of 39993 add up to 33, and repeating that until one digit is left gives the digital root 6. The Collatz sequence (halve if even, else 3n+1) takes 67 steps to reach 1.
LaTeX source of the formulas on this page
\[ 39993 = 3 \times 13331 \]
39993 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 53328 |
| Euler totient φ(n) | 26660 |
| Square | 1599440049 |
| Cube | 63966405879657 |
| Square root | 199.982499 |
| Digit sum / digital root | 33 / 6 |
| Collatz steps to 1 | 67 |
| Scientific notation | 3.9993 × |
39993 in other forms
| Form | Value |
|---|---|
| In words | thirty-nine thousand nine hundred and ninety-three |
| Binary (base 2) | 1001110000111001 |
| Octal (base 8) | 116071 |
| Hexadecimal (base 16) | 9C39 |
| Base 3 | 2000212020 |
| As time | 39993 seconds = 11 h 6 min 33 s |
Is 39993 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (39993 ÷ 3 = 13331) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 6) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 8) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 39993 a prime number?
No. 39993 = 3 × 13331, so it is divisible by 3.
What are the factors of 39993?
1, 3, 13331, 39993.
What is 39993 in binary?
1001110000111001 (hexadecimal 9C39, octal 116071).
What is the square root of 39993?
About 199.9825.
Is 39993 divisible by 3?
Yes. Its digits add up to 33, a multiple of 3.
What is special about the number 39993?
39993 is a palindrome: it reads 39993 backwards too; a binary palindrome (1001110000111001); a semiprime: 3 × 13331, the product of two primes.