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The number 39928

39928 is a composite number with 32 divisors. Its prime factorisation is 232^{3} × 7 × 23 × 31. Divisors (32): 1, 2, 4, 7, 8, 14, 23, 28, 31, 46, 56, 62, 92, 124, 161, 184 … 39928.

Number

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How to work it out

  1. 1

    What is special about 39928: a happy number: repeatedly adding the squares of its digits reaches 1; a Harshad number: divisible by its digit sum 31.

  2. 2

    39928 is composite. Its prime factorisation is

    39928=23×7×23×3139928 = 2^{3} \times 7 \times 23 \times 31
  3. 3

    The divisors add up to 92160; without 39928 itself that is 52232, so 39928 is abundant (52232 is more than 39928). Euler's totient φ(39928) = 15840 numbers up to 39928 share no factor with it.

  4. 4

    The digits of 39928 add up to 31, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 75 steps to reach 1.

LaTeX source of the formulas on this page
\[ 39928 = 2^{3} \times 7 \times 23 \times 31 \]

39928 at a glance

PropertyValue
Typecomposite
Number of divisors32
Sum of divisors92160
Euler totient φ(n)15840
Square1594245184
Cube63655021706752
Square root199.819919 (= 2√9982)
Digit sum / digital root31 / 4
Collatz steps to 175
Scientific notation3.9928 × 10410^{4}

39928 in other forms

FormValue
In wordsthirty-nine thousand nine hundred and twenty-eight
Binary (base 2)1001101111111000
Octal (base 8)115770
Hexadecimal (base 16)9BF8
Base 32000202211
As time39928 seconds = 11 h 5 min 28 s

Is 39928 divisible by 2 to 12?

DivisorAnswerRule
2Yes (39928 ÷ 2 = 19964)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4Yes (39928 ÷ 4 = 9982)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 4)A number is divisible by 6 if it is divisible by both 2 and 3.
7Yes (39928 ÷ 7 = 5704)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8Yes (39928 ÷ 8 = 4991)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 4)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 8)A number is divisible by 10 if the last digit is 0.
11No (remainder 9)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 4)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 39928 a prime number?

No. 39928 = 232^{3} × 7 × 23 × 31, so it is divisible by 2.

What are the factors of 39928?

1, 2, 4, 7, 8, 14, 23, 28, 31, 46, 56, 62, 92, 124, 161, 184, 217, 248, 322, 434, 644, 713, 868, 1288, 1426, 1736, 2852, 4991, 5704, 9982, 19964, 39928.

What is 39928 in binary?

1001101111111000 (hexadecimal 9BF8, octal 115770).

What is the square root of 39928?

About 199.8199, exactly 2√9982.

Is 39928 divisible by 3?

No. Its digits add up to 31, which is not a multiple of 3.

What is special about the number 39928?

39928 is a happy number: repeatedly adding the squares of its digits reaches 1; a Harshad number: divisible by its digit sum 31.

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