The number 33193
33193 is a composite number with 4 divisors. Its prime factorisation is 19 × 1747. Divisors (4): 1, 19, 1747, 33193.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 33193: a happy number: repeatedly adding the squares of its digits reaches 1; a Harshad number: divisible by its digit sum 19; a semiprime: 19 × 1747, the product of two primes.
- 2
33193 is composite. Its prime factorisation is
- 3
The divisors add up to 34960; without 33193 itself that is 1767, so 33193 is deficient (1767 is less than 33193). Euler's totient φ(33193) = 31428 numbers up to 33193 share no factor with it.
- 4
The digits of 33193 add up to 19, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 191 steps to reach 1.
LaTeX source of the formulas on this page
\[ 33193 = 19 \times 1747 \]
33193 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 34960 |
| Euler totient φ(n) | 31428 |
| Square | 1101775249 |
| Cube | 36571225840057 |
| Square root | 182.189462 |
| Digit sum / digital root | 19 / 1 |
| Collatz steps to 1 | 191 |
| Scientific notation | 3.3193 × |
33193 in other forms
| Form | Value |
|---|---|
| In words | thirty-three thousand one hundred and ninety-three |
| Binary (base 2) | 1000000110101001 |
| Octal (base 8) | 100651 |
| Hexadecimal (base 16) | 81A9 |
| Base 3 | 1200112101 |
| As time | 33193 seconds = 9 h 13 min 13 s |
Is 33193 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 1) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 33193 a prime number?
No. 33193 = 19 × 1747, so it is divisible by 19.
What are the factors of 33193?
1, 19, 1747, 33193.
What is 33193 in binary?
1000000110101001 (hexadecimal 81A9, octal 100651).
What is the square root of 33193?
About 182.1895.
Is 33193 divisible by 3?
No. Its digits add up to 19, which is not a multiple of 3.
What is special about the number 33193?
33193 is a happy number: repeatedly adding the squares of its digits reaches 1; a Harshad number: divisible by its digit sum 19; a semiprime: 19 × 1747, the product of two primes.