The number 33489

No. 33489 = 3^2 × 61^2, so it is divisible by 3.

33489 is a perfect square (183²). Its prime factorisation is $3^{2}$ × $61^{2}$ . Divisors (9): 1, 3, 9, 61, 183, 549, 3721, 11163, 33489.

Number

Pick any whole number from 1 to 100,000.

33489 = 3^{2} \times 61^{2}

How to work it out

1
What is special about 33489: a perfect square (183²).
2
33489 is composite. Its prime factorisation is
$33489 = 3^{2} \times 61^{2}$
3
The divisors add up to 49179; without 33489 itself that is 15690, so 33489 is deficient (15690 is less than 33489). Euler's totient φ(33489) = 21960 numbers up to 33489 share no factor with it.
4
The digits of 33489 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 111 steps to reach 1.

LaTeX source of the formulas on this page

\[ 33489 = 3^{2} \times 61^{2} \]

Form	Value
In words	thirty-three thousand four hundred and eighty-nine
Binary (base 2)	1000001011010001
Octal (base 8)	101321
Hexadecimal (base 16)	82D1
Base 3	1200221100
As time	33489 seconds = 9 h 18 min 9 s

Divisor	Answer	Rule
2	No (remainder 1)	A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3	Yes (33489 ÷ 3 = 11163)	A number is divisible by 3 if the digits add up to a multiple of 3.
4	No (remainder 1)	A number is divisible by 4 if the last two digits make a multiple of 4.
5	No (remainder 4)	A number is divisible by 5 if the last digit is 0 or 5.
6	No (remainder 3)	A number is divisible by 6 if it is divisible by both 2 and 3.
7	No (remainder 1)	A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8	No (remainder 1)	A number is divisible by 8 if the last three digits make a multiple of 8.
9	Yes (33489 ÷ 9 = 3721)	A number is divisible by 9 if the digits add up to a multiple of 9.
10	No (remainder 9)	A number is divisible by 10 if the last digit is 0.
11	No (remainder 5)	A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12	No (remainder 9)	A number is divisible by 12 if it is divisible by both 3 and 4.

Is 33489 a prime number?

No. 33489 = $3^{2}$ × $61^{2}$ , so it is divisible by 3.

What are the factors of 33489?

1, 3, 9, 61, 183, 549, 3721, 11163, 33489.

What is 33489 in binary?

1000001011010001 (hexadecimal 82D1, octal 101321).

What is the square root of 33489?

183, because 183 × 183 = 33489.

Is 33489 divisible by 3?

Yes. Its digits add up to 27, a multiple of 3.

What is special about the number 33489?

33489 is a perfect square (183²).