The number 32131
32131 is a triangular number: 1 + 2 + … + 253 = 32131. Its prime factorisation is 11 × 23 × 127. Divisors (8): 1, 11, 23, 127, 253, 1397, 2921, 32131.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 32131: a triangular number: 1 + 2 + … + 253 = 32131.
- 2
32131 is composite. Its prime factorisation is
- 3
The divisors add up to 36864; without 32131 itself that is 4733, so 32131 is deficient (4733 is less than 32131). Euler's totient φ(32131) = 27720 numbers up to 32131 share no factor with it.
- 4
The digits of 32131 add up to 10, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 46 steps to reach 1.
LaTeX source of the formulas on this page
\[ 32131 = 11 \times 23 \times 127 \]
32131 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 36864 |
| Euler totient φ(n) | 27720 |
| Square | 1032401161 |
| Cube | 33172081704091 |
| Square root | 179.251220 |
| Digit sum / digital root | 10 / 1 |
| Collatz steps to 1 | 46 |
| Scientific notation | 3.2131 × |
32131 in other forms
| Form | Value |
|---|---|
| In words | thirty-two thousand one hundred and thirty-one |
| Binary (base 2) | 111110110000011 |
| Octal (base 8) | 76603 |
| Hexadecimal (base 16) | 7D83 |
| Base 3 | 1122002001 |
| As time | 32131 seconds = 8 h 55 min 31 s |
Is 32131 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 1) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | Yes (32131 ÷ 11 = 2921) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 32131 a prime number?
No. 32131 = 11 × 23 × 127, so it is divisible by 11.
What are the factors of 32131?
1, 11, 23, 127, 253, 1397, 2921, 32131.
What is 32131 in binary?
111110110000011 (hexadecimal 7D83, octal 76603).
What is the square root of 32131?
About 179.2512.
Is 32131 divisible by 3?
No. Its digits add up to 10, which is not a multiple of 3.
What is special about the number 32131?
32131 is a triangular number: 1 + 2 + … + 253 = 32131.