The number 32121
32121 is a composite number with 12 divisors. Its prime factorisation is × 43 × 83. Divisors (12): 1, 3, 9, 43, 83, 129, 249, 387, 747, 3569, 10707, 32121.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 32121: a happy number: repeatedly adding the squares of its digits reaches 1; a Harshad number: divisible by its digit sum 9.
- 2
32121 is composite. Its prime factorisation is
- 3
The divisors add up to 48048; without 32121 itself that is 15927, so 32121 is deficient (15927 is less than 32121). Euler's totient φ(32121) = 20664 numbers up to 32121 share no factor with it.
- 4
The digits of 32121 add up to 9, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 253 steps to reach 1.
LaTeX source of the formulas on this page
\[ 32121 = 3^{2} \times 43 \times 83 \]32121 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 48048 |
| Euler totient φ(n) | 20664 |
| Square | 1031758641 |
| Cube | 33141119307561 |
| Square root | 179.223324 (= 3√3569) |
| Digit sum / digital root | 9 / 9 |
| Collatz steps to 1 | 253 |
| Scientific notation | 3.2121 × |
32121 in other forms
| Form | Value |
|---|---|
| In words | thirty-two thousand one hundred and twenty-one |
| Binary (base 2) | 111110101111001 |
| Octal (base 8) | 76571 |
| Hexadecimal (base 16) | 7D79 |
| Base 3 | 1122001200 |
| As time | 32121 seconds = 8 h 55 min 21 s |
Is 32121 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (32121 ÷ 3 = 10707) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (32121 ÷ 9 = 3569) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 32121 a prime number?
No. 32121 = × 43 × 83, so it is divisible by 3.
What are the factors of 32121?
1, 3, 9, 43, 83, 129, 249, 387, 747, 3569, 10707, 32121.
What is 32121 in binary?
111110101111001 (hexadecimal 7D79, octal 76571).
What is the square root of 32121?
About 179.2233, exactly 3√3569.
Is 32121 divisible by 3?
Yes. Its digits add up to 9, a multiple of 3.
What is special about the number 32121?
32121 is a happy number: repeatedly adding the squares of its digits reaches 1; a Harshad number: divisible by its digit sum 9.