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The number 18113

18113 is a composite number with 4 divisors. Its prime factorisation is 59 × 307. Divisors (4): 1, 59, 307, 18113.

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How to work it out

  1. 1

    What is special about 18113: a semiprime: 59 × 307, the product of two primes.

  2. 2

    18113 is composite. Its prime factorisation is

    18113=59×30718113 = 59 \times 307
  3. 3

    The divisors add up to 18480; without 18113 itself that is 367, so 18113 is deficient (367 is less than 18113). Euler's totient φ(18113) = 17748 numbers up to 18113 share no factor with it.

  4. 4

    The digits of 18113 add up to 14, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 40 steps to reach 1.

LaTeX source of the formulas on this page
\[ 18113 = 59 \times 307 \]

18113 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors18480
Euler totient φ(n)17748
Square328080769
Cube5942526968897
Square root134.584546
Digit sum / digital root14 / 5
Collatz steps to 140
Scientific notation1.8113 × 10410^{4}

18113 in other forms

FormValue
In wordseighteen thousand one hundred and thirteen
Binary (base 2)100011011000001
Octal (base 8)43301
Hexadecimal (base 16)46C1
Base 3220211212
As time18113 seconds = 5 h 1 min 53 s

Is 18113 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 4)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 5)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 7)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 5)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 18113 a prime number?

No. 18113 = 59 × 307, so it is divisible by 59.

What are the factors of 18113?

1, 59, 307, 18113.

What is 18113 in binary?

100011011000001 (hexadecimal 46C1, octal 43301).

What is the square root of 18113?

About 134.5845.

Is 18113 divisible by 3?

No. Its digits add up to 14, which is not a multiple of 3.

What is special about the number 18113?

18113 is a semiprime: 59 × 307, the product of two primes.

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