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The number 18103

18103 is a composite number with 4 divisors. Its prime factorisation is 43 × 421. Divisors (4): 1, 43, 421, 18103.

Number

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How to work it out

  1. 1

    What is special about 18103: a semiprime: 43 × 421, the product of two primes.

  2. 2

    18103 is composite. Its prime factorisation is

    18103=43×42118103 = 43 \times 421
  3. 3

    The divisors add up to 18568; without 18103 itself that is 465, so 18103 is deficient (465 is less than 18103). Euler's totient φ(18103) = 17640 numbers up to 18103 share no factor with it.

  4. 4

    The digits of 18103 add up to 13, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 92 steps to reach 1.

LaTeX source of the formulas on this page
\[ 18103 = 43 \times 421 \]

18103 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors18568
Euler totient φ(n)17640
Square327718609
Cube5932689978727
Square root134.547389
Digit sum / digital root13 / 4
Collatz steps to 192
Scientific notation1.8103 × 10410^{4}

18103 in other forms

FormValue
In wordseighteen thousand one hundred and three
Binary (base 2)100011010110111
Octal (base 8)43267
Hexadecimal (base 16)46B7
Base 3220211111
As time18103 seconds = 5 h 1 min 43 s

Is 18103 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 1)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 4)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 8)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 18103 a prime number?

No. 18103 = 43 × 421, so it is divisible by 43.

What are the factors of 18103?

1, 43, 421, 18103.

What is 18103 in binary?

100011010110111 (hexadecimal 46B7, octal 43267).

What is the square root of 18103?

About 134.5474.

Is 18103 divisible by 3?

No. Its digits add up to 13, which is not a multiple of 3.

What is special about the number 18103?

18103 is a semiprime: 43 × 421, the product of two primes.

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