Factors of 3745
The factors of 3745 are 1, 5, 7, 35, 107, 535, 749, 3745. It has 8 factors.
Pick any whole number from 1 to 10,000.
How to work it out
- 1
A factor of 3745 is a whole number that divides it with nothing left over. You only need to test the numbers up to √3745 ≈ 61.20; every one that divides gives a pair.
- 2
The factor pairs are listed in the table below. Together they give 8 factors.
- 3
Prime factorisation: keep dividing by the smallest prime that fits.
- 4
Add all the factors: 1 + 5 + 7 + 35 + 107 + 535 + 749 + 3745 = 5184. Without 3745 itself that is 1439, so 3745 is a deficient number.
LaTeX source of the formulas on this page
\[ 3745 = 5 \times 7 \times 107 \]
Factor pairs of 3745
| Factor | Pairs with | Product |
|---|---|---|
| 1 | 3745 | 1 × 3745 = 3745 |
| 5 | 749 | 5 × 749 = 3745 |
| 7 | 535 | 7 × 535 = 3745 |
| 35 | 107 | 35 × 107 = 3745 |
Questions
What are the factors of 3745?
The factors of 3745 are 1, 5, 7, 35, 107, 535, 749, 3745. It has 8 factors.
What are the prime factors of 3745?
5, 7, 107. As a product: 5 × 7 × 107.
How many factors does 3745 have?
3745 has 8 factors (4 factor pairs).
What is the sum of the factors of 3745?
5184.
Is 3745 a prime number?
No. It is divisible by 5, so 3745 = 5 × 749.