Factors of 3735
The factors of 3735 are 1, 3, 5, 9, 15, 45, 83, 249, 415, 747, 1245, 3735. It has 12 factors.
Pick any whole number from 1 to 10,000.
How to work it out
- 1
A factor of 3735 is a whole number that divides it with nothing left over. You only need to test the numbers up to √3735 ≈ 61.11; every one that divides gives a pair.
- 2
The factor pairs are listed in the table below. Together they give 12 factors.
- 3
Prime factorisation: keep dividing by the smallest prime that fits.
- 4
Add all the factors: 1 + 3 + 5 + 9 + 15 + 45 + 83 + 249 + 415 + 747 + 1245 + 3735 = 6552. Without 3735 itself that is 2817, so 3735 is a deficient number.
LaTeX source of the formulas on this page
\[ 3735 = 3^{2} \times 5 \times 83 \]Factor pairs of 3735
| Factor | Pairs with | Product |
|---|---|---|
| 1 | 3735 | 1 × 3735 = 3735 |
| 3 | 1245 | 3 × 1245 = 3735 |
| 5 | 747 | 5 × 747 = 3735 |
| 9 | 415 | 9 × 415 = 3735 |
| 15 | 249 | 15 × 249 = 3735 |
| 45 | 83 | 45 × 83 = 3735 |
Questions
What are the factors of 3735?
The factors of 3735 are 1, 3, 5, 9, 15, 45, 83, 249, 415, 747, 1245, 3735. It has 12 factors.
What are the prime factors of 3735?
3, 5, 83. As a product: × 5 × 83.
How many factors does 3735 have?
3735 has 12 factors (6 factor pairs).
What is the sum of the factors of 3735?
6552.
Is 3735 a prime number?
No. It is divisible by 3, so 3735 = 3 × 1245.