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One person does a job in 3 hours and another in 7 hours. How long together?

Working together they take 21/10 hours (about 2.1 hours, or 2 h 6 min).

How to work it out

  1. 1

    Think in rates: in one hour the first does 1/3 of the job and the second does 1/7.

  2. 2

    Together in one hour they do the sum of the rates:

    13+17=7+321=1021\frac{1}{3} + \frac{1}{7} = \frac{7 + 3}{21} = \frac{10}{21}
  3. 3

    If they do 10/21 of the job per hour, the whole job takes the reciprocal:

    t=2110=2110≈2.1 hourst = \frac{21}{10} = \frac{21}{10} \approx 2.1\text{ hours}
  4. 4

    Check: that is less than 3 hours, the faster worker alone, as it should be ✓

LaTeX source of the formulas on this page
\[ \frac{1}{3} + \frac{1}{7} = \frac{1}{t}\ \Rightarrow\ t = \frac{21}{10} \]
\[ \frac{1}{3} + \frac{1}{7} = \frac{7 + 3}{21} = \frac{10}{21} \]
\[ t = \frac{21}{10} = \frac{21}{10} \approx 2.1\text{ hours} \]

Questions

How long do they take together?

Working together they take 21/10 hours (about 2.1 hours, or 2 h 6 min).

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    One job takes 3 hours and another 7: together 2.1 hours | WordGPT