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One person does a job in 2 hours and another in 9 hours. How long together?

Working together they take 18/11 hours (about 1.6363636 hours, or 1 h 38 min).

How to work it out

  1. 1

    Think in rates: in one hour the first does 1/2 of the job and the second does 1/9.

  2. 2

    Together in one hour they do the sum of the rates:

    12+19=9+218=1118\frac{1}{2} + \frac{1}{9} = \frac{9 + 2}{18} = \frac{11}{18}
  3. 3

    If they do 11/18 of the job per hour, the whole job takes the reciprocal:

    t=1811=1811≈1.6363636 hourst = \frac{18}{11} = \frac{18}{11} \approx 1.6363636\text{ hours}
  4. 4

    Check: that is less than 2 hours, the faster worker alone, as it should be ✓

LaTeX source of the formulas on this page
\[ \frac{1}{2} + \frac{1}{9} = \frac{1}{t}\ \Rightarrow\ t = \frac{18}{11} \]
\[ \frac{1}{2} + \frac{1}{9} = \frac{9 + 2}{18} = \frac{11}{18} \]
\[ t = \frac{18}{11} = \frac{18}{11} \approx 1.6363636\text{ hours} \]

Questions

How long do they take together?

Working together they take 18/11 hours (about 1.6363636 hours, or 1 h 38 min).

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    One job takes 2 hours and another 9: together 1.6363636 hours | WordGPT