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One person does a job in 2 hours and another in 11 hours. How long together?

Working together they take 22/13 hours (about 1.6923077 hours, or 1 h 42 min).

How to work it out

  1. 1

    Think in rates: in one hour the first does 1/2 of the job and the second does 1/11.

  2. 2

    Together in one hour they do the sum of the rates:

    12+111=11+222=1322\frac{1}{2} + \frac{1}{11} = \frac{11 + 2}{22} = \frac{13}{22}
  3. 3

    If they do 13/22 of the job per hour, the whole job takes the reciprocal:

    t=2213=2213≈1.6923077 hourst = \frac{22}{13} = \frac{22}{13} \approx 1.6923077\text{ hours}
  4. 4

    Check: that is less than 2 hours, the faster worker alone, as it should be ✓

LaTeX source of the formulas on this page
\[ \frac{1}{2} + \frac{1}{11} = \frac{1}{t}\ \Rightarrow\ t = \frac{22}{13} \]
\[ \frac{1}{2} + \frac{1}{11} = \frac{11 + 2}{22} = \frac{13}{22} \]
\[ t = \frac{22}{13} = \frac{22}{13} \approx 1.6923077\text{ hours} \]

Questions

How long do they take together?

Working together they take 22/13 hours (about 1.6923077 hours, or 1 h 42 min).

Similar problems

    One job takes 2 hours and another 11: together 1.6923077 hours | WordGPT