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One person does a job in 11 hours and another in 11 hours. How long together?

Working together they take 11/2 hours (about 5.5 hours, or 5 h 30 min).

How to work it out

  1. 1

    Think in rates: in one hour the first does 1/11 of the job and the second does 1/11.

  2. 2

    Together in one hour they do the sum of the rates:

    111+111=11+11121=22121\frac{1}{11} + \frac{1}{11} = \frac{11 + 11}{121} = \frac{22}{121}
  3. 3

    If they do 22/121 of the job per hour, the whole job takes the reciprocal:

    t=12122=112≈5.5 hourst = \frac{121}{22} = \frac{11}{2} \approx 5.5\text{ hours}
  4. 4

    Check: that is less than 11 hours, the faster worker alone, as it should be ✓

LaTeX source of the formulas on this page
\[ \frac{1}{11} + \frac{1}{11} = \frac{1}{t}\ \Rightarrow\ t = \frac{11}{2} \]
\[ \frac{1}{11} + \frac{1}{11} = \frac{11 + 11}{121} = \frac{22}{121} \]
\[ t = \frac{121}{22} = \frac{11}{2} \approx 5.5\text{ hours} \]

Questions

How long do they take together?

Working together they take 11/2 hours (about 5.5 hours, or 5 h 30 min).

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    One job takes 11 hours and another 11: together 5.5 hours | WordGPT