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One person does a job in 10 hours and another in 10 hours. How long together?

Working together they take 5 hours.

How to work it out

  1. 1

    Think in rates: in one hour the first does 1/10 of the job and the second does 1/10.

  2. 2

    Together in one hour they do the sum of the rates:

    110+110=10+10100=20100\frac{1}{10} + \frac{1}{10} = \frac{10 + 10}{100} = \frac{20}{100}
  3. 3

    If they do 20/100 of the job per hour, the whole job takes the reciprocal:

    t=10020=5≈5 hourst = \frac{100}{20} = 5 \approx 5\text{ hours}
  4. 4

    Check: that is less than 10 hours, the faster worker alone, as it should be ✓

LaTeX source of the formulas on this page
\[ \frac{1}{10} + \frac{1}{10} = \frac{1}{t}\ \Rightarrow\ t = 5 \]
\[ \frac{1}{10} + \frac{1}{10} = \frac{10 + 10}{100} = \frac{20}{100} \]
\[ t = \frac{100}{20} = 5 \approx 5\text{ hours} \]

Questions

How long do they take together?

Working together they take 5 hours.

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