Taylor series of tan x up to degree 1

The Taylor polynomial of degree 1 for tan x about 0 (the Maclaurin polynomial) is x. The full series converges for |x| < π/2.

\tan\left(x\right) \approx x

tan x and its degree 1 Taylor polynomial. The polynomial hugs the curve inside the radius of convergence (π/2) and leaves it outside.

How to work it out

1
The Taylor series of f about 0 uses the derivatives of f at 0:
$f(x) = \sum_{k=0}^{\infty} \frac{f^{(k)}(0)}{k!}\,x^k$
2
For f(x) = tan x the first derivatives at 0 are:
$f^{(0)}(0) = 0,\quad f^{(1)}(0) = 1$
3
Divide each by k! and keep the terms up to degree 1:
$\tan\left(x\right) \approx x$
4
Radius of convergence: π/2 ≈ 1.5708. Inside it, more terms give a better approximation; outside, the series does not settle.

LaTeX source of the formulas on this page

\[ \tan\left(x\right) \approx x \]
\[ f(x) = \sum_{k=0}^{\infty} \frac{f^{(k)}(0)}{k!}\,x^k \]
\[ f^{(0)}(0) = 0,\quad f^{(1)}(0) = 1 \]

x	Polynomial	Exact	Error
0.1	0.10000000	0.10033467	3.35e-4
0.5	0.50000000	0.54630249	4.63e-2
0.9	0.90000000	1.2601582	3.60e-1
2	2.0000000	-2.1850399	4.19e+0

What is the Taylor series of tan x?

x + x³/3 + 2x⁵/15 + 17x⁷/315 + …

What is the degree 1 Taylor polynomial of tan x?

What is the radius of convergence of the series of tan x?

π/2 ≈ 1.5708

What is the Maclaurin series?

A Taylor series centred at 0.