Taylor series of ln(1 + x) up to degree 4
The Taylor polynomial of degree 4 for ln(1 + x) about 0 (the Maclaurin polynomial) is x - x²/2 + x³/3 - x⁴/4. The full series converges for |x| < 1.
How to work it out
- 1
The Taylor series of f about 0 uses the derivatives of f at 0:
- 2
For f(x) = ln(1 + x) the first derivatives at 0 are:
- 3
Divide each by k! and keep the terms up to degree 4:
- 4
Radius of convergence: 1 (converges for −1 < x ≤ 1). Inside it, more terms give a better approximation; outside, the series does not settle.
LaTeX source of the formulas on this page
\[ \ln\left(1 + x\right) \approx x - \frac{1}{2}x^{2} + \frac{1}{3}x^{3} - \frac{1}{4}x^{4} \]
\[ f(x) = \sum_{k=0}^{\infty} \frac{f^{(k)}(0)}{k!}\,x^k \]
\[ f^{(0)}(0) = 0,\quad f^{(1)}(0) = 1,\quad f^{(2)}(0) = -1,\quad f^{(3)}(0) = 2,\quad f^{(4)}(0) = -6 \]Degree 4 polynomial against the real ln(1 + x)
| x | Polynomial | Exact | Error |
|---|---|---|---|
| 0.1 | 0.095308333 | 0.095310180 | 1.85e-6 |
| 0.5 | 0.40104167 | 0.40546511 | 4.42e-3 |
| 0.9 | 0.57397500 | 0.64185389 | 6.79e-2 |
| 2 | -1.3333333 | 1.0986123 | 2.43e+0 |
Questions
What is the Taylor series of ln(1 + x)?
x - x²/2 + x³/3 - x⁴/4 + x⁵/5 - x⁶/6 + x⁷/7 - x⁸/8 + …
What is the degree 4 Taylor polynomial of ln(1 + x)?
x - x²/2 + x³/3 - x⁴/4
What is the radius of convergence of the series of ln(1 + x)?
1 (converges for −1 < x ≤ 1)
What is the Maclaurin series?
A Taylor series centred at 0.