Taylor series of arcsin x up to degree 1

The Taylor polynomial of degree 1 for arcsin x about 0 (the Maclaurin polynomial) is x. The full series converges for |x| < 1.

\arcsin\left(x\right) \approx x

arcsin x and its degree 1 Taylor polynomial. The polynomial hugs the curve inside the radius of convergence (1) and leaves it outside.

How to work it out

1
The Taylor series of f about 0 uses the derivatives of f at 0:
$f(x) = \sum_{k=0}^{\infty} \frac{f^{(k)}(0)}{k!}\,x^k$
2
For f(x) = arcsin x the first derivatives at 0 are:
$f^{(0)}(0) = 0,\quad f^{(1)}(0) = 1$
3
Divide each by k! and keep the terms up to degree 1:
$\arcsin\left(x\right) \approx x$
4
Radius of convergence: 1. Inside it, more terms give a better approximation; outside, the series does not settle.

LaTeX source of the formulas on this page

\[ \arcsin\left(x\right) \approx x \]
\[ f(x) = \sum_{k=0}^{\infty} \frac{f^{(k)}(0)}{k!}\,x^k \]
\[ f^{(0)}(0) = 0,\quad f^{(1)}(0) = 1 \]

x	Polynomial	Exact	Error
0.1	0.10000000	0.10016742	1.67e-4
0.5	0.50000000	0.52359878	2.36e-2
0.9	0.90000000	1.1197695	2.20e-1
2	2.0000000	undefined	-

What is the Taylor series of arcsin x?

x + x³/6 + 3x⁵/40 + 5x⁷/112 + …

What is the degree 1 Taylor polynomial of arcsin x?

What is the radius of convergence of the series of arcsin x?

What is the Maclaurin series?

A Taylor series centred at 0.